Firefighter Practice Exam 2026 - Free Firefighter Practice Questions and Study Guide

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What is the displacement of a piston with a bore of 3.25 inches and a stroke of 4.75 inches?

39.41 cubic inches

To find the displacement of a piston, you can use the formula for the volume of a cylinder, which is:

\[ \text{Volume} = \pi \times \left(\frac{\text{bore}}{2}\right)^2 \times \text{stroke} \]

In this case, the bore (diameter) is 3.25 inches, and the stroke (length of the piston travel) is 4.75 inches. First, you need to calculate the radius by halving the bore:

\[ \text{Radius} = \frac{3.25}{2} = 1.625 \text{ inches} \]

Next, you square the radius:

\[ \text{Radius}^2 = (1.625)^2 = 2.640625 \text{ square inches} \]

Now, multiply by the stroke and by π (approximately 3.14159):

\[ \text{Volume} = \pi \times 2.640625 \times 4.75 \]

Calculating this gives:

\[ \text{Volume} \approx 3.14159 \times 2.640625 \times 4.75 \approx 39.41 \

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47.59 cubic inches

132.52 cubic inches

157.62 cubic inches

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